A ball is thrown straight up at time t=0 with an initial speed of 19m/s. Take the point of release to be y0=0 and upwards to be the positive direction. Calculate the displacement at the time of 0.50 s
First we write the corresponding kinematics equations:  a = -g  v = -g * t + vo  y = -g * ((t ^ 2) / 2) + vo * t + yo  Substituting the values:  y = - (9.81) * (((0.50) ^ 2) / 2) + (19) * (0.50) + (0) = 8.27m  answer:  the displacement at the time of 0.50s is 8.27m
