PriyanaW346091 PriyanaW346091
  • 03-11-2022
  • Mathematics
contestada

help me please i want to see if i did it correctly

help me please i want to see if i did it correctly class=

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HaddoxT283581 HaddoxT283581
  • 03-11-2022

-1/16

1) Considering that we have the following identity:

[tex]\begin{gathered} \cos (2x)=2\cos (2x)-1 \\ \end{gathered}[/tex]

2) We can plug into that the cos (x).:

[tex]\begin{gathered} \cos (2x)=(\frac{\sqrt[]{15}}{4})^2-1 \\ \cos (2x)=\frac{15}{16}-\frac{16}{15} \\ \cos (2x)=-\frac{1}{16} \end{gathered}[/tex]

Since for the Quadrant II cosine yields a negative value.

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