MaviY379785 MaviY379785

03-11-2022
Mathematics

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help me solve the equation for precalcules please and thank you

help me solve the equation for precalcules please and thank you class=

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BaronD210780 BaronD210780

03-11-2022

343^(3-2p) = 7^2

343 = 7^3

Hence 343^(3-2p) = 7^2

7^3(3-2p) = 7^2

Equating the base

3(3-2p) = 2

expand

9 - 6p = 2

subtract 9 from both sides

-6p = 2 - 9

-6p = -7

Divide both sides by -6

p = -7/-6

p = 7/6

p = 1.167

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