pirvandarius
pirvandarius pirvandarius
  • 01-11-2016
  • Mathematics
contestada

determinati toate numerele naturale cuprinse intre 50 si 250 care la impartirea cu 3,8 si 12 dau ,de fiecare data ,restul 1

Respuesta :

syed514
syed514 syed514
  • 13-11-2016
pentru nr.
3;
8;
12
cmmmc=  2 la 3+*3=24;
se calculeaza multiplii lui 24 si rezulta 24*1= 24
24*3=72,
24*4=96;
24*5=120;
24*6=144;
24*7=168;
24*8=192;
24*9=216;
24*10=240;
Pentru a indeplini conditia la numerele cuprinse intre 50 si 250 se mai aduga 1 si obtinem:
73;
97;
121;
145;
169;
193;
217;
241
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