Dimajago Dimajago

03-07-2020
Mathematics

contestada

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Respuesta :

09pqr4sT 09pqr4sT

03-07-2020

Answer:

0

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

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