Respuesta :

gmany

[tex]\left\{\begin{array}{ccc}-\dfrac{1}{4}x+y=-2&|\cdot4\\-x+4y=-8\end{array}\right\\\\\left\{\begin{array}{ccc}-x+4y=-8\\-x+4y=-8\end{array}\right\\\\-x+4y=-8\ \ \ \ |+x\\4y=x-8\ \ \ \ |:4\\y=\dfrac{1}{4}x+2\\\\\left\{\begin{array}{ccc}x\in\mathbb{R}\\\\y=\dfrac{1}{4}x+2\end{array}\right[/tex]

Otras preguntas